JEE Mains · Physics · STD 12 - 12. atoms
The longest wavelength associated with Paschen series is _______. (Given \(R_H=1.097 \times 10^7 \mathrm{SI}\) unit)
- A \(1.094 \times 10^{-6} \mathrm{~m}\)
- B \(2.973 \times 10^{-6} \mathrm{~m}\)
- C \(3.646 \times 10^{-6} \mathrm{~m}\)
- D \(1.876 \times 10^{-6} \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(1.876 \times 10^{-6} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
For longest wavelength in Paschen's series: \(\frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{\mathrm{n}_1{ }^2}-\frac{1}{\mathrm{n}_2{ }^2}\right]\) \(\text { For longest } \mathrm{n}_1=3\) \(\frac{1}{\lambda}=\mathrm{n}\left[\frac{1}{(3)^2}-\frac{1}{(4)^2}\right]\)…
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