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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

In a moving coil galvanometer, two moving coils \(M_1\) and \(M_2\) have the following particulars :
\(\begin{aligned}
& \mathrm{R}_1=5 \Omega, \mathrm{~N}_1=15, \mathrm{~A}_1=3.6 \times 10^{-3} \mathrm{~m}^2, \mathrm{~B}_1=0.25 \mathrm{~T} \\
& \mathrm{R}_2=7 \Omega, \mathrm{~N}_2=21, \mathrm{~A}_2=1.8 \times 10^{-3} \mathrm{~m}^2, \mathrm{~B}_2=0.50 \mathrm{~T}
\end{aligned}\)
Assuming that torsional constant of the springs are same for both coils, what will be the ratio of voltage sensitivity of \(M_1\) and \(M_2\) ?

  1. A \(1: 1\)
  2. B \(1: 4\)
  3. C \(1: 3\)
  4. D \(1: 2\)
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Answer & Solution

Correct Answer

(A) \(1: 1\)

Step-by-step Solution

Detailed explanation

\(\text { Voltage sensitivity }=\frac{\theta}{V}=\frac{N A B}{c R} \)…
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