JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2020
- Medium
- MCQ
The current \(i\) in the network is.....\(A\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(0.3 \)
Step-by-step Solution
Detailed explanation
\(i=\frac{9}{(5+10+5+10)}=\frac{9}{30} A\)


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