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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2020
  • Medium
  • MCQ

The current \(i\) in the network is.....\(A\)

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Verified Solution

Answer & Solution

Correct Answer

(C) \(0.3 \)

Step-by-step Solution

Detailed explanation

\(i=\frac{9}{(5+10+5+10)}=\frac{9}{30} A\)
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