JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2023
- Medium
- Numerical
Work done by a Carnot engine operating between temperatures \(127^{\circ}\,C\) and \(27^{\circ}\,C\) is \(2\,kJ\). The amount of heat transferred to the engine by the reservoir is \(........\,kJ\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
\(\eta=1-\frac{ T _2}{ T _1}=\frac{ W }{ Q _1}\)
\(\Rightarrow \frac{ W }{ Q _1}=1-\frac{300}{400}=\frac{1}{4}\)
\(\Rightarrow \frac{2 kJ }{ Q _1}=\frac{1}{4}\)
\(\Rightarrow Q _1=8\,kJ\)
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