JEE Mains · Physics · STD 11 - 11. thermodynamics
A Carnot engine has efficiency of \(50 \%\). If the temperature of sink is reduced by \(40^{\circ} C\), its efficiency increases by \(30 \%\). The temperature of the source will be\(....K\)
- A \(166.7\)
- B \(255.1\)
- C \(266.7\)
- D \(367.7\)
Answer & Solution
Correct Answer
(C) \(266.7\)
Step-by-step Solution
Detailed explanation
\(\eta=1-\frac{ T _{ L }}{ T _{ H }}\) \(\frac{1}{2}=1-\frac{ T _{ L }}{ T _{ H }}\) \(\frac{1}{2}(1.3)=1-\left(\frac{ T _{ L }-40}{ T _{ H }}\right)\) \(\frac{1}{2}(1.3)=\frac{1}{2}+\frac{40}{ T _{ H }} \quad T _{ H }=266.7\,K\)
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