JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2026
- Easy
- MCQ
Two identical circular loops P and Q each of radius r are lying in parallel planes such that they have common axis. The current through P and Q are I and 4I respectively in clockwise direction as seen from O . The net magnetic field at O is:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{3\mu_{0}I}{4\sqrt{2}r}\) towards Q
Step-by-step Solution
Detailed explanation
\(B _{ net }= B _1- B _2\)
\(=\frac{4 \mu_0 i R^2}{2\left(R^2+R^2\right)^{3 / 2}}-\frac{\mu_0 i R^2}{2\left(R^2+R^2\right)^{3 / 2}}\)
\(=\frac{3 \mu_0 i }{4 \sqrt{2} R}\)
\(=\frac{4 \mu_0 i R^2}{2\left(R^2+R^2\right)^{3 / 2}}-\frac{\mu_0 i R^2}{2\left(R^2+R^2\right)^{3 / 2}}\)
\(=\frac{3 \mu_0 i }{4 \sqrt{2} R}\)
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