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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2020
  • Hard
  • MCQ

A bead of mass \(m\) stays at point \(P ( a , b )\) on a wire bent in the shape of a parabola \(y=4 Cx ^{2}\) and rotating with angular speed \(\omega\) (see figure). The value of \(\omega\) is (neglect friction)

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Answer & Solution

Correct Answer

(B) \(2 \sqrt{2 g C}\)

Step-by-step Solution

Detailed explanation

In rotating frame

\(mx \omega^{2} \cos \theta= mg \sin \theta\)

\(x \omega^{2}= g \tan \theta\)

\(x \omega^{2}= g \cdot \frac{ dy }{ dx }\)

\(x \omega^{2}= g \cdot(8 cx )\)

\(\omega^{2}=8 gc\)

\(\omega=2 \sqrt{2 gc }\)

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