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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Medium
  • Numerical

A series combination of resistor of resistance \(100\,\Omega\), inductor of inductance \(1\,H\) and capacitor of capacitance \(6.25\,\mu F\) is connected to an ac source. The quality factor of the circuit will be \(.............\).

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Answer & Solution

Correct Answer

(A) \(4\)

Step-by-step Solution

Detailed explanation

\(\text { Quality factor }=\frac{X_L}{R}=\frac{\omega L}{R}\)

\(\omega=\frac{1}{\sqrt{ LC }}=\frac{1}{\sqrt{1 \times 6.25 \times 10^{-6}}}=\frac{10^3}{2.5}=400 / sec\)

\(\text { Q-factor }=\frac{400 \times 1}{100}=4\)

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