JEE Mains · Chemistry · STD 11 - 7. Redox reactions
\(2 IO _3^{-}+ xI ^{-}+12 H ^{+} \rightarrow 6 I _2+6 H _2 O\) What is the value of \(x\) ?
- A \(12\)
- B \(2\)
- C \(6\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
Number of atoms of iodine on reactant side \(=\) number of atoms of Iodine on product side \(2+ x =6 \times 2\) \(X =10\) \(2 IO _3^{-}+10 I ^{-}+12 H ^{+} \rightarrow 6 I _2+6 H _2 O\)
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