JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
1.24 g of \(\mathrm{AX}_2\) (molar mass \(124 \mathrm{~g} \mathrm{~mol}^{-1}\) ) is dissolved in 1 kg of water to form a solution with boiling point of \(100.0156^{\circ} \mathrm{C}\), while \(25.4 \mathrm{~g}^{\circ}\) of \(\mathrm{AY}_2\) (molar mass \(250 \mathrm{~g} \mathrm{~mol}^{-1}\) ) in 2 kg of water constitutes a solution with a boiling point of \(100.0260^{\circ} \mathrm{C}\).
\(\mathrm{K}_{\mathrm{b}}\left(\mathrm{H}_2 \mathrm{O}\right)=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) Which of the following is correct ?
- A \(\mathrm{AX}_2\) is fully ionised while \(\mathrm{AY}_2\) is completely unionised.
- B \(\mathrm{AX}_2\) is completely unionised while \(\mathrm{AY}_2\) is fully ionised.
- C \(\mathrm{AX}_2\) and \(\mathrm{AY}_2\) (both) are completely unionised.
- D \(\mathrm{AX}_2\) and \(\mathrm{AY}_2\) (both) are fully ionised.
Answer & Solution
Correct Answer
(A) \(\mathrm{AX}_2\) is fully ionised while \(\mathrm{AY}_2\) is completely unionised.
Step-by-step Solution
Detailed explanation
For \(\mathrm{AX}_2\) \(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{i} \mathrm{~K} \mathrm{~m} \\ & 0.0156=\mathrm{i} \times 0.52 \times \frac{1.24}{124 \times 1} \\ & 3=\mathrm{i} \\ & 3=1+2 \alpha \\ & 1=\alpha \end{aligned}\) For \(\mathrm{AY}_2\)…
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