JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The rate of first order reaction is \(0.04 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) at \(10\) minutes and \(0.03 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) at \(20\) minutes after initiation. Half life of the reaction is _______ minutes. (Given \(\log 2=0.3010, \log 3=0.4771)\)
- A \(24\)
- B \(30\)
- C \(35\)
- D \(40\)
Answer & Solution
Correct Answer
(A) \(24\)
Step-by-step Solution
Detailed explanation
\(0.04=\mathrm{k}[\mathrm{A}]_0 \mathrm{e}^{-\mathrm{k} \times 10 \times 60}\) \(...(1)\) \(0.03=\mathrm{k}[\mathrm{A}]_0 \mathrm{e}^{-\mathrm{k} \times 20 \times 60}\) \(...(2)\) \((1) /(2)\) \(\frac{4}{3}=\mathrm{e}^{600 \mathrm{k}(2-1)}\)…
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