JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The amount of sugar \((C_{12}H_{22}O_{11})\) required to prepare \(2\, L\) of its \(0.1\, M\) aqueous solution is ............... \(\mathrm{g}\)
- A \(136.8\)
- B \(17.1\)
- C \(68.4\)
- D \(34.2\)
Answer & Solution
Correct Answer
(C) \(68.4\)
Step-by-step Solution
Detailed explanation
\(0.1 = \frac{{{n_{{C_{12}} + {H_{22}} + {O_{11}}}}}}{2}\) \({n_{{C_{12}} + {H_{22}} + {O_{11}}}} = 0.2\) \(W{t_{{C_{12}} + {H_{22}} + {O_{11}}}} = 0.2 \times 342 = 68.4\)
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