JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Three moles of an ideal gas are compressed isothermally from \(60 \mathrm{~L}\) to \(20 \mathrm{~L}\) using constant pressure of \(5 \mathrm{~atm}\). Heat exchange \(Q\) for the compression is _______ Lit. atm.
- A \(199\)
- B \(100\)
- C \(200\)
- D \(300\)
Answer & Solution
Correct Answer
(C) \(200\)
Step-by-step Solution
Detailed explanation
As isothermal \(\Delta \mathrm{U}=0\) and process is irreversible \(\mathrm{Q}=-\mathrm{W}=-\left[-\mathrm{P}_{\mathrm{ext}}\left(\mathrm{V}_2-\mathrm{V}_1\right)\right]\) \(\mathrm{Q}=5(20-60)=-200 \mathrm{~atm}-\mathrm{L}\)
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