JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
A constant current was passed through a solution of \(\mathrm{AuCl}_4^{-}\)ion between gold electrodes. After a period of \(10.0\) minutes, the increase in mass of cathode was \(1.314 \mathrm{~g}\). The total charge passed through the solution is _______ \(\times 10^{-2} \mathrm{~F}\). (Given atomic mass of \({\mathrm{Au}}={197}\) )
- A \(2\)
- B \(3\)
- C \(4\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{W}}{\mathrm{E}}=\frac{\text { ch arge }}{1 \mathrm{~F}} \) \(\frac{1.314}{\frac{197}{3}}=\frac{\mathrm{Q}}{1 \mathrm{~F}}\) \(\mathrm{Q}=2 \times 10^{-2} \mathrm{~F}\)
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