JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
On complete combustion \(0.30 \,g\) of an organic compound gave \(0.20\, g\) of carbon dioxide and \(0.10\, g\) of water. The percentage of carbon in the given organic compound is \(.....\) (Nearest Integer)
- A \(18\)
- B \(180\)
- C \(65\)
- D \(74\)
Answer & Solution
Correct Answer
(A) \(18\)
Step-by-step Solution
Detailed explanation
\(C _{ x } HyOz +\left( x +\frac{ y }{4}-\frac{ z }{2}\right) O _{2} \rightarrow xCO _{2}+\frac{ y }{2} H _{2} O\) \(0.3g\quad\quad\quad\quad\quad\quad\quad\quad0.2g\quad\quad\quad0.1g\) \(\frac{ n _{ CO _{2}}}{ n _{ H _{2} O }}=\frac{ x }{ y / 2}=\frac{0.2 / 44}{.1 / 18}\)…
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