JEE Mains · Chemistry · STD 11 - 2. structure of atom
The de Broglie wavelength of an electron in the \(4^{th}\) Bohr orbit is
- A \(8 \pi a_{0}\)
- B \(2 \pi a_{0}\)
- C \(4 \pi a_{0}\)
- D \(6 \pi a_{0}\)
Answer & Solution
Correct Answer
(A) \(8 \pi a_{0}\)
Step-by-step Solution
Detailed explanation
\(2 \pi r=n \lambda\) for \(\quad \mathrm{n}=1, \mathrm{r}=\mathrm{a}_{0}\) \(\mathrm{n}=4, \mathrm{r}=16 \mathrm{a}_{0}\) So, \(\quad 2 \pi \times 16 \mathrm{a}_{0}=4 \times \lambda\) \(\lambda=8 \pi \mathrm{a}_{0}\)
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