JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
For the following reaction the mass of water produced from \(445\,g\) of \(C_{57}H_{110}O_6\) is .............. \(\mathrm{g}\) \(2{C_{57}}{H_{110}}{O_6}(s)\, + \,163\,{O_2}(g)\, \to \,114\,C{O_2}(g)\, +\) \(\,110\,{H_2}O(l)\)
- A \(490\)
- B \(445\)
- C \(495\)
- D \(890\)
Answer & Solution
Correct Answer
(C) \(495\)
Step-by-step Solution
Detailed explanation
\(2{C_{57}}{H_{110}}{O_6}(s) + 163{O_2}(g) \to \) \(114C{O_2}(g) + 110{H_2}O(l)\) \(\frac{{Moles\,of\,{C_{57}}{H_{110}}{O_6}}}{2} = \frac{{Moles\,of\,{H_2}O}}{{110}}\) \(\frac{{\frac{{445}}{{890}}}}{2} = \frac{{\frac{{Mass\,of\,{H_2}O}}{{18}}}}{{110}}\) Mass of \(H_2O = 495\,g\)
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