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JEE Mains · Physics · STD 11 - Surface tension
  • JEE Mains 2025
  • Medium
  • Numerical

An air bubble of radius 1.0 mm is observed at a depth of 20 cm below the free surface of a liquid having surface tension \(0.095 \mathrm{~J} / \mathrm{m}^2\) and density \(10^3 \mathrm{~kg} / \mathrm{m}^3\). The difference between pressure inside the bubble and atmospheric pressure is _____ \(\mathrm{N} / \mathrm{m}^2\). (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) )

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Answer & Solution

Correct Answer

(A) 2190

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Detailed explanation


\(\Delta \mathrm{P}=\mathrm{P}_{\mathrm{in}}-\mathrm{P}_0\)
\(\begin{aligned} & =\rho \mathrm{gh}+\frac{2 \mathrm{~T}}{\mathrm{R}}=\frac{1000 \times 10 \times 20}{100}+\frac{2 \times 0.095}{10^{-3}} \\ & =2000+190 \\ & =2190\end{aligned}\)
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