JEE Mains · Physics · STD 11 - 9.2 surface tension
An air bubble of radius 1.0 mm is observed at a depth of 20 cm below the free surface of a liquid having surface tension \(0.095 \mathrm{~J} / \mathrm{m}^2\) and density \(10^3 \mathrm{~kg} / \mathrm{m}^3\). The difference between pressure inside the bubble and atmospheric pressure is _____ \(\mathrm{N} / \mathrm{m}^2\). (Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) )
- A 2190
- B 2000
- C 1540
- D 1325
Answer & Solution
Correct Answer
(A) 2190
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{P}=\mathrm{P}_{\mathrm{in}}-\mathrm{P}_0\) \(\begin{aligned} & =\rho \mathrm{gh}+\frac{2 \mathrm{~T}}{\mathrm{R}}=\frac{1000 \times 10 \times 20}{100}+\frac{2 \times 0.095}{10^{-3}} \\ & =2000+190 \\ & =2190\end{aligned}\)
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