JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The minimum amount of \(O_2\,(g)\) consumed per gram of reactant is for the reaction : (Given atomic mass : \(Fe = 56,\,\,O = 16,\,\,Mg = 24,\,\,\)\(P = 31,\,\,C = 12,\,\,H = 1\) )
- A \(C_3H_8(g) + 5O_2(g) \to 3CO_2(g) + 4H_2O(l)\)
- B \(P_4(s) + 5O_2(g) \to P_4O_{10}(s)\)
- C \(4Fe(s) + 3O_2(g) \to 2Fe_2O_3(s)\)
- D \(2Mg(s) + O_2(g) \to 2MgO(s)\)
Answer & Solution
Correct Answer
(C) \(4Fe(s) + 3O_2(g) \to 2Fe_2O_3(s)\)
Step-by-step Solution
Detailed explanation
\(4\,mol\) of \(Fe\) require \(3 \times 32\,gram\) \(\frac {1}{56}\,mol\) of \(Fe\) require \(=\frac {3\times 32}{4}\,\times \frac {1}{56}\,=\,0.428\,g\)
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