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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

Standard enthalpy of vapourisation for \(\mathrm{CCl}_4\) is \(30.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Heat required for vapourisation of \(284 \mathrm{~g}\) of \(\mathrm{CCl}_4\) at constant temperature is _______ \(\mathrm{kJ}\). (Given molar mass in \(\mathrm{g} \mathrm{mol}^{-1} ; \mathrm{C}=12, \mathrm{Cl}=35.5\) )

  1. A \(78\)
  2. B \(12\)
  3. C \(46\)
  4. D \(56\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(56\)

Step-by-step Solution

Detailed explanation

\( \Delta \mathrm{H}_{\text {vap }}^0 \mathrm{CCl}_4=30.5 \mathrm{~kJ} / \mathrm{mol} \) \( \text { Mass of } \mathrm{CCl}_4=284 \mathrm{gm} \) \( \text { Molar mass of } \mathrm{CCl}_4=154 \mathrm{~g} / \mathrm{mol} \)…