JEE Mains · Chemistry · STD 12 - p -Block elements - ll
Xenon hexafluoride on partial hydrolysis produces compounds \('X'\) and \('Y'\) . Compounds \('X'\) and \('Y'\) and the oxidation state of \(Xe\) are respectively
- A \(XeOF_4(+6)\) and \(XeO_3(+6)\)
- B \(XeO_2(+4)\) and \(XeO_3(+6)\)
- C \(XeOF_4(+6)\) and \(XeO_2F_2(+6)\)
- D \(XeO_2F_2(+6)\) and \(XeO_2(+4)\)
Answer & Solution
Correct Answer
(C) \(XeOF_4(+6)\) and \(XeO_2F_2(+6)\)
Step-by-step Solution
Detailed explanation
\(Xe{{F}_{6}}\,+\,{{H}_{2}}O\,\xrightarrow[hydrolysis]{particle}\underset{'X'}{\mathop{\overset{+6}{\mathop{Xe}}\,O{{F}_{4}}}}\,\,+\,2HF\) \(Xe\mathop {O{F_4}}\limits_{'X'} \, + {H_2}O\, \to \mathop {\mathop {Xe}\limits^{ + 6} {O_2}{F_2}}\limits_{'Y'} \, + \,2HF\)
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