JEE Mains · Chemistry · STD 11 - 2. structure of atom
The graph between \({\left| \psi \right|^2}\) and \(r\)(radial distance) is shown below. This represents
- A \(1s\) orbital
- B \(3s\) orbital
- C \(2s\) orbital
- D \(2p\) orbital
Answer & Solution
Correct Answer
(C) \(2s\) orbital
Step-by-step Solution
Detailed explanation
As we know that for \(s-\) orbital graph start from top and no. of radial node \(= n-l-1\) For \(2s\) orbital it will \(= 2-0-1=1\) \(\therefore \) The graph is of \(2s\)
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