ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2023
  • Hard
  • MCQ

A \(10\,\mu C\) charge is divided into two parts and placed at \(1\,cm\) distance so that the repulsive force between them is maximum. The charges of the two parts are :

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(5\,\mu C , 5\,\mu C\)

Step-by-step Solution

Detailed explanation

Divide \(q =10\,\mu C\) into two parts \(x\) and \(q - x\)

\(F =\frac{K x(q-x)}{r^2}\)

For \(F\) to be maximum

\(\frac{d F}{d x}=\frac{K}{r^2}(q-2 x)=0\)

\(x =\frac{ q }{2}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app