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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2020
  • Hard
  • MCQ

The acceleration due to gravity on the earth's surface at the poles is \(g\) and angular velocity of the earth about the axis passing through the pole is \(\omega .\) An object is weighed at the equator and at a height \(h\) above the poles by using a spring balance. If the weights are found to be same, then \(h\) is \(:( h << R ,\) where \(R\) is the radius of the earth)

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Answer & Solution

Correct Answer

(D) \(\frac{ R ^{2} \omega^{2}}{2 g }\)

Step-by-step Solution

Detailed explanation

\(g _{ e }= g - R \omega^{2}\)

\(g_{2}=g\left(1-\frac{2 h}{R}\right)\)

\(g_{2}=g-\frac{2 g h}{R}\)

Now \(R \omega^{2}=\frac{2 g h}{R}\)

\(h=\frac{R^{2} \omega^{2}}{2 g}\)

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