JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Production of iron in blast furnace follows the following equation \(Fe _{3} O _{4}( s )+4 CO ( g ) \rightarrow 3 Fe ( l )+4 CO _{2}( g )\) when \(4.640 \,kg\) of \(Fe _{3} O _{4}\) and \(2.520 \,kg\) of \(CO\) are allowed to react then the amount of iron (in \(g\) ) produced is \(....\) [Given : Molar Atomic mass \(\left( g\, mol ^{-1}\right): Fe =56\) Molar Atomic mass \(\left( g \,mol ^{-1}\right): 0=16\) Molar Atomic mass \(\left( g\, mol ^{-1}\right):= C =12\)
- A \(1400\)
- B \(2200\)
- C \(3360\)
- D \(4200\)
Answer & Solution
Correct Answer
(C) \(3360\)
Step-by-step Solution
Detailed explanation
Moles of \(Fe _{3} O _{4}=\frac{4.640 \times 10^{3}}{232}=20\) Moles of \(CO =\frac{2.52 \times 10^{3}}{28}=90\) So limiting Reagent \(= Fe _{3} O _{4}\) So moles of \(Fe\) formed \(=60\) Weight of \(Fe =60 \times 56=3360\, gms\)
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