JEE Mains · Physics · STD 11 - 14. waves and sound
For a certain organ pipe, the first three resonance frequencies are in the ratio of \(1:3:5\) respectively. If the frequency of fifth harmonic is \(405\,Hz\) and the speed of sound in air is \(324 \,ms ^{-1}\) the length of the organ pipe is \(..........m.\)
- A \(0\)
- B \(2\)
- C \(3\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
For \(5^{\text {th }}\) harmonic in closed organ pipe, \(f _5=\frac{5 V }{4 \ell} \Rightarrow 405=\frac{5 \times 324}{4 \ell}\) \(\Rightarrow \ell=1 \,\)
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