JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For the reaction, \(2A + B\,\to \) products , when the concentrations of \(A\) and \(B\) both were doubled, the rate of the reaction increased from \(0.3\,mol\,L^{-1}\,s^{-1}\) to \(2.4 \,mol\,L^{-1}\,s^{-1}.\) When the concentration of \(A\) alone is doubled, the rate increased from \(0.3\,mol\,L^{-1}\,s^{-1}\) to \(0.6\,mol\,L^{-1}\,s^{-1}.\) Which one of the following statements is correct?
- A Total order of the reaction is \(4\)
- B Order of the reaction with respect to \(B\) is \(2\)
- C Order of the reaction with respect to \(B\) is \(1\)
- D Order of the reaction with respect to \(A\) is \(2\)
Answer & Solution
Correct Answer
(B) Order of the reaction with respect to \(B\) is \(2\)
Step-by-step Solution
Detailed explanation
\(2A+B\to \) products Rate \(=\,K\,[A]^x[B]^y\) \(r\,=\,K\,[A]^x[B]^y\) ..... \((i)\) \(0.3\,=\,K\,[A]^x[B]^y\) ..... \((1)\) \(2.4\, = \,K{[2A]^x}\,{[2B]^y}\) ...... \((2)\) \(0.6\, = \,K{[2A]^x}\,{[B]^y}\) ...... \((3)\) From \((1)\,(2)\) and \((3)\) \(X\,=\,1,\) \(Y\,=\,2\)…
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