JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(SO _{2} Cl _{2}\) on reaction with excess of water results into acidic mixture \(SO _{2} Cl _{2}+2 H _{2} O \rightarrow H _{2} SO _{4}+2 HCl\) \(16\,moles\) of \(NaOH\) is required for the complete neutralisation of the resultant acidic mixture. The number of moles of \(SO _{2} Cl _{2}\) used is.
- A \(16\)
- B \(8\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
Let \(n\left( SO _{2} Cl _{2}\right)= x\) moles \(\therefore n \left( H _{2} SO _{4}\right)= x , n ( HCl )=2 x\) \(n \left( H ^{+}\right)=4\,x\) For Neutralisation \(n \left( H ^{+}\right)= n \left( OH ^{-}\right)\) \(4 x =16\) \(x =4\)
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