JEE Mains · Physics · STD 12 -6. Electromagnetic induction
The current in an inductor is given by \(\mathrm{I}=(3 \mathrm{t}+8)\) where \(t\) is in second. The magnitude of induced emf produced in the inductor is \(12 \mathrm{mV}\). The selfinductance of the inductor _______ \(\mathrm{mH}\).
- A \(3\)
- B \(4\)
- C \(6\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}=3 \mathrm{t}+8\) \(\varepsilon=12 \mathrm{mV}\) \(|\varepsilon|=\mathrm{L}\left|\frac{\mathrm{dI}}{\mathrm{dt}}\right|\) \(12=\mathrm{L} \times 3\) \(\mathrm{~L}=4 \mathrm{mH}\)
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