JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Of the following four aqueous solutions, total number of those solutions whose freezing point is lower than that of \(0.10\, \mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) is (Integer answer) \((i)\) \(0.10\, \mathrm{M} \,\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) \((ii)\) \(0.10\, \mathrm{M}\, \mathrm{Na}_{2} \mathrm{SO}_{4}\) \((iii)\) \(0.10\, \mathrm{M}\, \mathrm{KCl}\) \((iv)\) \(0.10 \,\mathrm{M} \,\mathrm{Li}_{3} \mathrm{PO}_{4}\)
- A \(4\)
- B \(3\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(4\)
Step-by-step Solution
Detailed explanation
As \(0.1 \,\mathrm{M} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) is non-dissociative and rest all salt given are electrolyte so in each case effective molarity \(>\,0.1\) so each will have lower freezing point.
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