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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

Match the LIST-I with LIST-II
List-I
Thermodynamic Process
List-II
Magnitude in kJ
A. Work done in reversible, isothermal expansion of 2 mol of ideal gas from 2 \(dm ^3\) to \(20 dm ^3\) at 300 K.I. 4
B. Work done in irreversible isothermal expansion of 1 mol ideal gas from \(1 m^3\) to \(3 m^3\) at 300 K against A constant pressure of 3 kPa .II. 11.5
C. Change in internal energy for adiabatic expansion of a 1 mol ideal gas with change of temperature \(=320 K\) and \(\overline{ C }_{ V }=\frac{3}{2} R\).III. 6
D. Change in enthalpy at constant pressure of 1 mole ideal gas with change of temperature \(=\) 337 K and \(\overline{ C }_{ P }=\frac{5}{2} R\).IV. 7
Choose the correct answer from the option given below :

  1. A A-III, B-II, C-IV, D-I
  2. B A-II, B-III, C-I, D-IV
  3. C A-I, B-II, C-III, D-IV
  4. D A-II, B-I, C-III, D-IV
Verified Solution

Answer & Solution

Correct Answer

(B) A-II, B-III, C-I, D-IV

Step-by-step Solution

Detailed explanation

Option (A) \( \begin{array}{l} W=-nRT \ln \frac{V_2}{V_1} \\ =\frac{-2 \times 8.314 \times 300}{1000} \times \ln \left(\frac{20}{2}\right) kJ \\ =-11.5 kJ \end{array} \) Option (B) \( \begin{array}{l} W=-P_{\text {ext }}\left[V_2-V_1\right] \\ =-3[3-1] \\ =-6 kJ \end{array} \)…
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