JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Match the LIST-I with LIST-II
| List-I Thermodynamic Process | List-II Magnitude in kJ |
| A. Work done in reversible, isothermal expansion of 2 mol of ideal gas from 2 \(dm ^3\) to \(20 dm ^3\) at 300 K. | I. 4 |
| B. Work done in irreversible isothermal expansion of 1 mol ideal gas from \(1 m^3\) to \(3 m^3\) at 300 K against A constant pressure of 3 kPa . | II. 11.5 |
| C. Change in internal energy for adiabatic expansion of a 1 mol ideal gas with change of temperature \(=320 K\) and \(\overline{ C }_{ V }=\frac{3}{2} R\). | III. 6 |
| D. Change in enthalpy at constant pressure of 1 mole ideal gas with change of temperature \(=\) 337 K and \(\overline{ C }_{ P }=\frac{5}{2} R\). | IV. 7 |
- A A-III, B-II, C-IV, D-I
- B A-II, B-III, C-I, D-IV
- C A-I, B-II, C-III, D-IV
- D A-II, B-I, C-III, D-IV
Answer & Solution
Correct Answer
(B) A-II, B-III, C-I, D-IV
Step-by-step Solution
Detailed explanation
Option (A) \( \begin{array}{l} W=-nRT \ln \frac{V_2}{V_1} \\ =\frac{-2 \times 8.314 \times 300}{1000} \times \ln \left(\frac{20}{2}\right) kJ \\ =-11.5 kJ \end{array} \) Option (B) \( \begin{array}{l} W=-P_{\text {ext }}\left[V_2-V_1\right] \\ =-3[3-1] \\ =-6 kJ \end{array} \)…
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