JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Match List \(I\) with List \(II\):
| List \(I\) (Complexes) | List \(II\) (Hybridisation) |
| \(A\) \(\left[ Ni ( CO )_4\right]\) | \(I\) \(sp ^3\) |
| \(B\) \(\left[ Cu \left( NH _3\right)_4\right]^{2+}\) | \(II\) \(dsp^2\) |
| \(C\) \(\left[ Fe \left( NH _3\right)_6\right]^{2+}\) | \(III\) \(sp^3d^2\) |
| \(D\) \(\left[ Fe \left( H _2 O \right)_6\right]^{2+}\) | \(IV\) \(d^2sp^3\) |
- A \(A - II, B - I, C - III, D - IV\)
- B \(A - I, B - II, C - III, D - IV\)
- C \(A - II, B - I, C - IV, D - III\)
- D \(A - I, B- II, C - IV, D - III\)
Answer & Solution
Correct Answer
(D) \(A - I, B- II, C - IV, D - III\)
Step-by-step Solution
Detailed explanation
For \(\left[ Fe \left( NH _3\right)_6\right]^{+2}, \Delta_0 < P\), hence the pairing of electrons does not occur in \(t_{2 g}\). Therefore complex is outer orbital and its hybridisation is \(sp ^3 d ^2\). List \(I\) (Complexes) List \(II\) (Hybridisation) \(A\)…
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