JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The equilibrium constant at \(298\, K\) for a reaction \(A + B \rightleftharpoons C + D\) is \(100.\) If the initial concentration of all the four species were \(1\, M\) each, then equilibrium concentration of \(D\) ( in \(mol\, L^{-1}\) ) will be :
- A \(1.818\)
- B \(1.182\)
- C \(0.182\)
- D \(0.818\)
Answer & Solution
Correct Answer
(A) \(1.818\)
Step-by-step Solution
Detailed explanation
\(A + B \rightleftharpoons C + D\) No. of moles Initialy \(1\) \(1\) \(1\) \(1\) At equillibrium \(1-a\) \(1-a\) \(1+a\) \(1+a\) \(\therefore K_{c}=\left(\frac{1+a}{1-a}\right)^{2}=100\) \(\therefore \quad \frac{1+a}{1-a}=10\) On solving \(a=0.81\)…
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