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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

A student has studied the decomposition of a gas \(AB _3\) at \(25^{\circ} C\). He obtained the following data.
\(p ( mm Hg )\) \(50\) \(100\) \(200\) \(400\)
Relative \(t _{1 / 2}( s )\) \(4\) \(2\) \(1\) \(0.5\)
The order of the reaction is

  1. A \(0.5\)
  2. B \(2\)
  3. C \(1\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(t _{1 / 2} \propto\left( P _0\right)^{1- n }\) \(\frac{\left( t _{1 / 2}\right)_1}{\left( t _{1 / 2}\right)_2}=\frac{\left( P _0\right)_1^{1- n }}{\left( P _{0_2}\right)_2^{1- n }}\) \(\Rightarrow\left(\frac{4}{2}\right)=\left(\frac{50}{100}\right)^{1- n }\)…
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