JEE Mains · Chemistry · STD 11 - 8.2 Organic chemistry isomerism
Optical activity of an enantiomeric mixture is \(+12.6^{\circ}\) and the specific rotation of \((t)\) isomer is \(+30^{\circ}\). The optical purity is \(........\%\)
- A \(41\)
- B \(43\)
- C \(44\)
- D \(42\)
Answer & Solution
Correct Answer
(D) \(42\)
Step-by-step Solution
Detailed explanation
\(\%\) optical purity \(=\frac{\text { observed rotation of mixture } \times 100}{\text { rotation of pure enantiomer }}\) \(=\frac{+12.6^{\circ}}{+30^{\circ}} \times 100=42\)
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