JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Given below are two statements:
Statement I: The number of species among \( BF_{4}^{-}, SiF_{4}, XeF_{4} \) and \( SF_{4} \), that have unequal E-F bond lengths is two. Here, E is the central atom.
Statement II: Among \(O _2^{-}, O _2^{2-}, F _2\) and \(O _2^{+}, O _2^{-}\)has the highest bond order.
In the light of the above statements, choose the correct answer from the options given below
- A Both Statement I and Statement II are false
- B Both Statement I and Statement II are true
- C Statement I is true but Statement II is false
- D Statement I is false but Statement II is true
Answer & Solution
Correct Answer
(A) Both Statement I and Statement II are false
Step-by-step Solution
Detailed explanation
In \(BF _4^{-}, SiF _4\) and \(XeF _4\) all bond lengths are identicalMolecules B.O. \(O _2^{+}\) → 2.5 \(O_2^{-}\) → 1.5 \(O _2^{2-}\) → 1 \(F_2\) → 1
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Calculate the standard cell potential (in \(V\)) of the cell in which following reaction takes place \(F{e^2}+ \left( {aq} \right) + A{g^ + }\left( {aq} \right) \to F{e^{3 + }}\left( {aq} \right) + Ag\left( s \right)\) Given that:
\(E_{Ag^+/Ag}^o = xV\)
\(E_{F{e^{2 + }}/Fe}^o = yV\)
\(E_{F{e^{3 + }}/Fe}^o = zV\)JEE Mains 2019 Hard - A solution is prepared by adding \(2\,g\) of " \(X\) " of \(1\,mole\) of water. Mass percent of " \(X\) " in the solution is \(.............\%\)JEE Mains 2023 Medium
- Which of the following statements about \(Na_2O_2\) is not correctJEE Mains 2014 Medium
- \(10\, mL\) of \(1\,mM\) surfactant solution forms a monolayer covering \(0.24\, cm^2\) on a polar substrate. If the polar head is approximated as cube, what is its edge length ?JEE Mains 2019 Hard
- The elemental composition of a compound is \(54.2 \% \mathrm{C}, 9.2 \% \mathrm{H}\) and \(36.6 \% \mathrm{O}\).
If the molar mass of the compound is \(132 \mathrm{~g} \mathrm{~mol}^{-1}\), the molecular formula of the compound is :
[Given : The relative atomic mass of \(\mathrm{C}: \mathrm{H}: \mathrm{O}=12: 1: 16\) ]JEE Mains 2025 Easy - Given below are two statements :
Statement (I) : Molal depression constant \(\mathrm{K}_{\mathrm{f}}\) is given by \(\frac{M_1 R T_f}{\Delta S_{f u s}}\), where symbols have their usual meaning.
Statement (II) : \(\mathrm{K}_{\mathrm{f}}\) for benzene is less than the \(\mathrm{K}_{\mathrm{f}}\) for water.
In the light of the above statements, choose the most appropriate answer from the options given below :JEE Mains 2025 Medium
More PYQs from JEE Mains
- If \( \alpha \) and \( \beta \) \( (\alpha < \beta) \) are the roots of the equation \( (-2+\sqrt{3})(|\sqrt{x}-3|) + (x-6\sqrt{x}) + (9-2\sqrt{3}) = 0 \), \( x \ge 0 \), then \( \sqrt{\frac{\beta}{\alpha}} + \sqrt{\alpha\beta} \) is equal to:JEE Mains 2026 Easy
- Which one of the following complexes will consume more equivalents of aqueous solution of \(AgNO_3\) ?JEE Mains 2016 Hard
- If the distance of the earth from Sun is \(1.5 \times 10^6\,km\). Then the distance of an imaginary planet from Sun, if its period of revolution is \(2.83\) years is \(.............\times 10^6\,km\)JEE Mains 2023 Medium
- \(1.86\, g\) of aniline completely reacts to form acetanilide. \(10 \,\%\) of the product is lost during purification. Amount of acetanilide obtained after purification (in \(g\)) is ...... \(\times 10^{-2}.\)JEE Mains 2021 Hard
- \(2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{~g})\) The above reaction is carried out in a vessel starting with partial pressure \(\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}\) \(bar,\) \(\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}\) \(bar\) and \(\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}\). When the reaction is complete, the total pressure in the reaction vessel is \(.....\mathrm{m}\) \(bar.\) (Round off to the Nearest Integer).JEE Mains 2021 Medium
- Let \(f: \mathrm{R} \rightarrow \mathrm{R}\) be a function given by \(f(x)= \begin{cases}\frac{1-\cos 2 x}{x^2} & , x<0 \\ \alpha & , x=0, \text { where } \alpha, \beta \in R \text {. If } \\ \frac{\beta \sqrt{1-\cos x}}{x} & , x>0\end{cases}\) \(f\) is continuous at \(\mathrm{x}=0\), then \(\alpha^2+\beta^2\) is equal to :JEE Mains 2024 Medium