JEE Mains · Chemistry · STD 11 - 2. structure of atom
The ground state energy of hydrogen atom is \(-13.6\, eV\). The energy of second excited state of \(He^+\) ion in \(eV\) is
- A \(-54.4\)
- B \(-3.4\)
- C \(-6.04\)
- D \(-27.2\)
Answer & Solution
Correct Answer
(C) \(-6.04\)
Step-by-step Solution
Detailed explanation
\(E = - 13.6\frac{{{z^2}}}{{{n^2}}}\,eV\) \(E_{He}^ + = - 13.6\frac{4}{9}\)
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