ExamBro
ExamBro
JEE Mains · Chemistry · STD 12 - p -Block elements - ll

Given below are two statements:
Statement I: The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.
Statement II: A group 15 element's hydride \(EH_{3}\) has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4.
In the light of the above statements, choose the correct answer from the options given below.

  1. A Both Statement I and Statement II are true.
  2. B Statement I is false but Statement II is true.
  3. C Both Statement I and Statement II are false.
  4. D Statement I is true but Statement II is false.
Verified Solution

Answer & Solution

Correct Answer

(C) Both Statement I and Statement II are false.

Step-by-step Solution

Detailed explanation

\(HF < HCl < HBr < HI\) (bond length order) \(F < Cl < Br < I\) (radius order) \(PH _3< AsH _3< NH _3< SbH _3< BiH _3\) (Boiling point order) Maximum possible covalency of phosphorous is 6
From JEE Mains
Explore more questions on app