JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
For a reaction \(A \rightarrow 2 B + C\) the half lives are \(100\,s\) and \(50\,s\) when the concentration of reactant \(A\) is \(0.5\) and \(1.0 \,mol\,L ^{-1}\) respectively. The order of the reaction is (Nearest Integer)
- A \(2\)
- B \(1\)
- C \(3\)
- D \(0\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(t _{\frac{1}{2}} \propto \frac{1}{\left[ A _{0}\right]^{ n -1}}\) \([100] \propto \frac{1}{(0.5)^{n-1}}\) \((50) \propto \frac{1}{(1)^{n-1}}\) \([2]^{1}=\left[\frac{1}{0.5}\right]^{ n -1}\) \([2]^{1}=[2]^{n-1}\) \(n -1=1\) \(n=2\) \(\text { order }=2\)
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