JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
The resistance of a galvanometer is \(50\, ohm\) and the maximum current which can be passed through it is \(0.002\, A\). What resistance must be connected to it in order to convert it into an ammeter of range \(0 -0.5\, A\) ?....\(ohm\)
- A \(0.2\)
- B \(0.002\)
- C \(0.02\)
- D \(0.5\)
Answer & Solution
Correct Answer
(A) \(0.2\)
Step-by-step Solution
Detailed explanation
since shunt resistance is connected in parallel with galvanometer, both will have same voltage drop. \((0.002)\left(R_{G}\right)=(0.5-0.002)\left(r_{s}\right)\) \(\Rightarrow r_{s} \approx 0.2\, \Omega\)
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