JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2021
- Hard
- MCQ
An inductor coil stores \(64\, {J}\) of magnetic field energy and dissipates energy at the rate of \(640\, {W}\) when a current of \(8\, {A}\) is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(0.2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{U}=\frac{1}{2} \mathrm{Li}^{2}=64 \Rightarrow \mathrm{L}=2\)
\(\mathrm{i}^{2} \mathrm{R}=640\)
\(\mathrm{R}=\frac{640}{(8)^{2}}=10\)
\(\tau=\frac{\mathrm{L}}{\mathrm{R}}=\frac{1}{5}=0.2\)
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