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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2021
  • Hard
  • MCQ

An inductor coil stores \(64\, {J}\) of magnetic field energy and dissipates energy at the rate of \(640\, {W}\) when a current of \(8\, {A}\) is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds

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Answer & Solution

Correct Answer

(D) \(0.2\)

Step-by-step Solution

Detailed explanation

\(\mathrm{U}=\frac{1}{2} \mathrm{Li}^{2}=64 \Rightarrow \mathrm{L}=2\)

\(\mathrm{i}^{2} \mathrm{R}=640\)

\(\mathrm{R}=\frac{640}{(8)^{2}}=10\)

\(\tau=\frac{\mathrm{L}}{\mathrm{R}}=\frac{1}{5}=0.2\)

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