JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
Identify the molecule \(( X )\) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among \(HNO _3, H _2 SO _4, NF _3\) and \(O _3\). Choose the correct bond angle made by the central atom of the molecule (X).
- A \(120^{\circ}\)
- B \(107^{\circ}\)
- C \(102^{\circ}\)
- D \(116^{\circ}\)
Answer & Solution
Correct Answer
(C) \(102^{\circ}\)
Step-by-step Solution
Detailed explanation
\(N F _{ 3 }\) , hybridization : \(sp ^3\) Number of lone pair in \(NF _3=10\) Bond angle in \(NF _3 \approx 102^{\circ}\)
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