JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2022
- Medium
- Numerical
A ball is projected from the ground with a speed \(15 \,ms ^{-1}\) at an angle \(\theta\) with horizontal so that its range and maximum height are equal, then \(tan\,\theta\) will be equal to
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
\(R = H\)
\(\frac{2 v _{ x } \times v _{ y }}{ g }=\frac{ v _{ y }^{2}}{2 g }\)
\(v _{ x }=\frac{ v _{ y }}{4} ; u \cos \theta=\frac{ u \sin \theta}{4}\)
\(\tan \theta=4\)
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