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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2022
  • Medium
  • Numerical

A ball is projected from the ground with a speed \(15 \,ms ^{-1}\) at an angle \(\theta\) with horizontal so that its range and maximum height are equal, then \(tan\,\theta\) will be equal to 

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Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

\(R = H\)

\(\frac{2 v _{ x } \times v _{ y }}{ g }=\frac{ v _{ y }^{2}}{2 g }\)

\(v _{ x }=\frac{ v _{ y }}{4} ; u \cos \theta=\frac{ u \sin \theta}{4}\)

\(\tan \theta=4\)

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