JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Consider the following reaction \(N _{2} O _{4}( g ) \rightleftharpoons 2 NO _{2}( g ) ; \Delta H ^{0}=+58 kJ\) For each of the following cases \((a, b),\) the direction in which the equilibrium shifts is: \((a)\) Temperature is decreased \((b)\) Pressure is increased by adding \(N _{2}\) at constant \(T\)
- A \((a)\) towards reactant, \((b)\) no change
- B \((a)\) towards product, \((b)\) towards reactant
- C \((a)\) towards product, \((b)\) no change
- D \((a)\) towards reactant, \((b)\) towards product
Answer & Solution
Correct Answer
(A) \((a)\) towards reactant, \((b)\) no change
Step-by-step Solution
Detailed explanation
\(\Delta H ^{\circ}>0 \quad T \downarrow\) equation shifts back ward. \(N _{2}\) is treated as inert gas in this case hence no effect on equilibrium.
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