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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

A uniform solid cylinder of mass ' \(m\) ' and radius ' \(r\) ' rolls along an inclined rough plane of inclination \(45^{\circ}\). If it starts to roll from rest from the top of the plane then the linear acceleration of the cylinder's axis will be

  1. A \(\frac{1}{\sqrt{2}} \mathrm{~g}\)
  2. B \(\frac{1}{3 \sqrt{2}} \mathrm{~g}\)
  3. C \(\frac{\sqrt{2} \mathrm{~g}}{3}\)
  4. D \(\sqrt{2} g\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\sqrt{2} \mathrm{~g}}{3}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & a=\frac{\mathrm{g} \sin \theta}{1+\frac{\mathrm{I}}{\mathrm{mR}^2}} \\ & a=\frac{\frac{g}{\sqrt{2}}}{1+\frac{1}{2}}=\frac{2 \frac{g}{\sqrt{2}}}{3}=\frac{\sqrt{2} g}{3}\end{aligned}\)
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