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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2020
  • Medium
  • MCQ

If the screw on a screw-gauge is given six rotations, it moves by \(3\; \mathrm{mm}\) on the main scale. If there are \(50\) divisions on the circular scale the least count of the screw gauge is

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Answer & Solution

Correct Answer

(B) \(0.001\; cm\)

Step-by-step Solution

Detailed explanation

On six rotation, reading of main scale changes by \(3 \mathrm{mm} .\)

1 rotation corresponds to \(\frac{1}{2} \mathrm{mm}\)

Also no. of division on circular scale \(=50 .\)

Least count of the screw gauge will be

\(\frac{0.5}{50} \mathrm{mm}=0.001 \mathrm{cm}\)

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