JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
For the cell \(Zn(s)|\,Z{n^{2 + }}(aq)\,||\,{M^x+} \,(aq)|\,M(s),\) different half cells and their standard electrode potentials are given below
| \(M^{x+}\, (aq)\,/M(s)\) | \(A{u^{3 + }}(aq)/\) \(Au(s)\) | \(A{g^ + }(aq)/\) \(Ag(s)\) | \(F{e^{3 + }}(aq)/\) \(F{e^{2 + }}(aq)\) | \(F{e^{2 + }}(aq)/\) \(Fe(s)\) |
| \(E^o\,M^{x+}\) \(\,/M(V)\) | \(1.40\) | \(0.80\) | \(0.77\) | \(-0.44\) |
- A \(Ag^+\,/\,Ag\)
- B \(Fe^{3+}\,/\,Fe^{2+}\)
- C \(Au^{3+}\,/\,Au\)
- D \(Fe^{2+}\,/\,Fe\)
Answer & Solution
Correct Answer
(C) \(Au^{3+}\,/\,Au\)
Step-by-step Solution
Detailed explanation
\(E_{cell}^o{\kern 1pt} = E_{Cathode}^o\, - \,E_{Z{n^{2 + }}/Zn}^o\) Since \(Au^{3+} \to Au\) has maximum value.
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