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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

For the cell \(Zn(s)|\,Z{n^{2 + }}(aq)\,||\,{M^x+} \,(aq)|\,M(s),\) different half cells and their standard electrode potentials are given below
  \(M^{x+}\,  (aq)\,/M(s)\) \(A{u^{3 + }}(aq)/\) \(Au(s)\)   \(A{g^ + }(aq)/\) \(Ag(s)\) \(F{e^{3 + }}(aq)/\) \(F{e^{2 + }}(aq)\) \(F{e^{2 + }}(aq)/\) \(Fe(s)\)
  \(E^o\,M^{x+}\) \(\,/M(V)\)   \(1.40\)   \(0.80\)   \(0.77\)    \(-0.44\)
If \(E_{Z{n^{2 + }}/Zn}^o =  - 0.76\,V,\) which cathode will given a maximum value of  \(E_{cell}^o\) per electron transferred?

  1. A \(Ag^+\,/\,Ag\)
  2. B \(Fe^{3+}\,/\,Fe^{2+}\)
  3. C \(Au^{3+}\,/\,Au\)
  4. D \(Fe^{2+}\,/\,Fe\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(Au^{3+}\,/\,Au\)

Step-by-step Solution

Detailed explanation

\(E_{cell}^o{\kern 1pt} = E_{Cathode}^o\, - \,E_{Z{n^{2 + }}/Zn}^o\) Since \(Au^{3+} \to Au\) has maximum value.