JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
An external pressure \(P\) is applied on a cube at \(0^o C\) so that it is equally compressed from all sides. \(K\) is the bulk modulus of the material of the cube and a is its coefficient of linear expansion. Suppose we want to bring the cube to its original size by heating. The temperature should be raised by
- A \(\frac{P}{{3\alpha K}}\)
- B \(\;\frac{P}{{\alpha K}}\)
- C \(\;\frac{{3\alpha }}{{PK}}\)
- D \(\;3PK\alpha \)
Answer & Solution
Correct Answer
(A) \(\frac{P}{{3\alpha K}}\)
Step-by-step Solution
Detailed explanation
As we know , Bulk modulus \(K = \frac{{\Delta P}}{{\left( {\frac{{ - \Delta V}}{V}} \right)}} \Rightarrow \frac{{\Delta V}}{V} = \frac{P}{K}\) \(V = {V_0}\left( {1 + \gamma \Delta t} \right)\) \(\frac{{\Delta V}}{{{V_0}}} = \gamma \Delta t\)…
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