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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

A prism of refractive index \(\mu\) and angle \(A\) is placed in the minimum deviation position. If the angle of minimum deviation is \(A,\) then the value of \(A\) in terms of \(\mu\) is

  1. A \({\sin ^{ - 1}}\left( {\frac{\mu }{2}} \right)\)
  2. B \({\sin ^{ - 1}}\sqrt {\frac{{\mu - 1}}{2}} \)
  3. C \(2{\cos ^{ - 1}}\left( {\frac{\mu }{2}} \right)\)
  4. D \({\cos ^{ - 1}}\left( {\frac{\mu }{2}} \right)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2{\cos ^{ - 1}}\left( {\frac{\mu }{2}} \right)\)

Step-by-step Solution

Detailed explanation

(c) Given \({\delta _m} = A,\) as \(\mu = \frac{{\sin \,\left({\frac{{A + {\delta _m}}}{2}} \right)}}{{\sin \,\left({\frac{A}{2}} \right)}}\) \( \Rightarrow \)\(\mu = \frac{{\sin \left({\frac{{A + A}}{2}} \right)}}{{\sin \left({\frac{A}{2}} \right)}} = 2\cos \frac{A}{2} \)…
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