JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Given: \(C{o^{3 + }}{e^ - } \longrightarrow C{o^{2 + }};\,{E^o} = 1.81\,V\) \(P{b^4} + 2{e^ - } \longrightarrow P{b^{2 + }};\,{E^o} = + 1.67\,V\) \(C{e^{4 + }} + {e^ - } \longrightarrow C{e^{3 + }};\,{E^o} = + 1.61\,V\) \(B{i^{3 + }} + 3{e^ - } \longrightarrow Bi;\,{E^o} = + 0.20\,V\) Oxidizing power of the species will increase in the order
- A \(C{e^{4 + }} < P{b^{4 + }} < B{i^{3 + }} < C{o^{3 + }}\)
- B \(C{o^{3 + }} < P{b^{4 + }} < C{e^{4 + }} < B{i^{3 + }}\)
- C \(B{i^{3 + }} < C{e^{4 + }} < P{b^{4 + }} < C{o^{3 + }}\)
- D \(C{o^{3 + }} < C{e^{4 + }} < B{i^{3 + }} < P{b^{4 + }}\)
Answer & Solution
Correct Answer
(C) \(B{i^{3 + }} < C{e^{4 + }} < P{b^{4 + }} < C{o^{3 + }}\)
Step-by-step Solution
Detailed explanation
Lower the standard reduction potential, more the ability to get reduced higher the oxidizing power
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